Thirty-Six

Unit 9 · Advanced TopicsN4 · Complex Numbers · Propulsion

Complex Numbers

Use i squared equals negative one, multiply cleanly, and divide with conjugates.

  • 28 min
  • Unlocks: Plasma Chamber

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7 steps · about 28 minutes

Start with the warm-up.

Start

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Warm-up

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Key terms

imaginary unit
The number i defined by i squared equals negative one.
complex number
A number a+bi.
conjugate
For a+bi, the conjugate is a-bi.

Start by naming the quantity each problem asks for. That habit blocks the most common ACT trap.

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Try it first

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Take a calm first shot. Label what you know, write one relationship, and make the best choice you can.

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The big idea

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Build the picture before the arithmetic

Powers of i repeat every four. To divide complex numbers, multiply numerator and denominator by the denominator conjugate so the denominator becomes real.

Key idea

The decision that matters

Treat i like an algebraic symbol during expansion, then replace every i squared with -1.

Imaginary unit
i2=1i^2=-1

Write this relationship before inserting numbers. It keeps labels and units attached to the work.

A compact example

(3+2i)(4i)=123i+8i2i2=14+5i(3+2i)(4-i)=12-3i+8i-2i^2=14+5i.

CueBest move
Power of ireduce exponent modulo 4
Complex denominatormultiply by its conjugate

Trap

Replacing i squared with 1

This error produces a believable answer. Pause before computing and say what each number means.

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Worked examples

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Skip check · 2 questions

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Worked example

Example 1: Square a complex binomial

Problem

Simplify (32i)2(3-2i)^2.
Expand all three terms: 912i+4i29-12i+4i^2.

Replace i2i^2 with 1-1: 912i49-12i-4.

Which expansion correctly squares the complex binomial?

Combine real parts: 512i5-12i.

Why must the cross term and i squared both be handled?

Worked example

Example 2: Divide using a conjugate

Problem

Write 4+i2i\frac{4+i}{2-i} in the form a+bia+bi.
Multiply numerator and denominator by the conjugate 2+i2+i.

Numerator: (4+i)(2+i)=7+6i(4+i)(2+i)=7+6i. Denominator: (2i)(2+i)=5(2-i)(2+i)=5.

Which factor makes the complex denominator real?

The quotient is 7/5+(6/5)i7/5+(6/5)i.

Why does multiplying by the conjugate preserve the quotient?

Faded example · you finish it

Example 3: You finish it

Problem

Complete i27=i24i3=__i^{27}=i^{24}i^3=\_\_.
Reduce the exponent modulo 4 and use the repeating cycle 1,i,1,i1,i,-1,-i.

Which completion is correct?

Which reason validates the result?

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Optional · 4 questions · Hardest levelChallenge set: the kind of question that decides a 36

These are last-ten-questions hard. Take your time, use Desmos when it helps, and expect to miss some: that's where the learning is.