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Key terms
amplitude
Half the vertical distance from a sinusoid minimum to maximum.
period
The horizontal length of one full cycle.
included angle
The angle between two named sides.
Start by naming the quantity each problem asks for. That habit blocks the most common ACT trap.
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Step 2 of 7·Try it firstDone
Try it first
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Take a calm first shot. Label what you know, write one relationship, and make the best choice you can.
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Step 3 of 7·LearnDone
The big idea
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Build the picture before the arithmetic
First ask whether a right angle is guaranteed. For y=Asin(Bx), the amplitude is ∣A∣ and the period in degrees is ∣B∣360∘. For oblique triangles, write the appropriate law before substituting.
Key idea
The decision that matters
Use the triangle information to choose the law: a known angle-opposite-side pair points to sines; two sides with their included angle points to cosines.
Law of cosines
c2=a2+b2−2abcosC
Write this relationship before inserting numbers. It keeps labels and units attached to the work.
A compact example
If a=7, b=10, and C=60∘, then c2=72+102−2(7)(10)cos60∘=79, so c=79.
Explore in Desmos
Read amplitude and period from a trig graph
Keep degree mode on. Read the maximum and minimum y-values to get amplitude 4, then locate two consecutive maxima to get the 120° period. Change 3 to 2 and verify that the period becomes 180°.
The calculator is live: change anything and see what happens.
Read amplitude and period from a trig graph
Degree mode
Press Escape to leave the calculator (twice if a menu is open).
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Cue
Best move
Trig graph
Use the outside coefficient for amplitude and the inside factor for period
Oblique triangle
SAS uses cosine; known opposite pairs use sine
Trap
Using SOH-CAH-TOA on a nonright triangle
This error produces a believable answer. Pause before computing and say what each number means.
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Step 4 of 7·Worked examplesDone
Worked examples
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Skip check · 2 questions
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Worked example
Example 1: Read a sinusoid
Problem
For y=−4cos(3x), with x in degrees, find the amplitude and period.
Amplitude is the absolute value of the outside coefficient: ∣−4∣=4.
Period is 360∘/∣3∣=120∘.
What are the amplitude and period of this cosine graph?
The negative reflects the graph; it does not make amplitude negative.
Why do the coefficient 4 and factor 3 give those graph features?
Worked example
Example 2: Use the law of cosines
Problem
Two sides of a triangle are 8 and 11, and their included angle is 60∘. Find the square of the opposite side c.
This is side-angle-side, so use c2=a2+b2−2abcosC.
c2=82+112−2(8)(11)cos60∘.
Which substitution correctly uses the included angle?
Since cos60∘=1/2, c2=64+121−88=97.
Why is the law of cosines appropriate here?
Faded example · you finish it
Example 3: You finish it
Problem
In a triangle, side 10 is opposite 40∘ and side b is opposite 65∘. Complete the setup.
Match each side with its opposite angle before writing a sine-law proportion.
Which completion is correct?
Which reason validates the result?
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Step 5 of 7·PracticeDone
Practice
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Step 6 of 7·Spot the mistakeDone
Spot the mistake
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Spot the mistake
Where did it go wrong?
One line has an error. Click the line where it first goes wrong.
What went wrongA factor of 2 makes the cycle happen twice as fast, so the period must get shorter.
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Step 7 of 7·Exit ticketDone
Exit ticket
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Optional · 4 questions · Hardest levelChallenge set: the kind of question that decides a 36
These are last-ten-questions hard. Take your time, use Desmos when it helps, and expect to miss some: that's where the learning is.